Purpose:
- To determine which materials/solutions conduct electricity and why.
M
aterials:
- 5% NaCl solution
- Solid NaCl
- 5% sucrose (C12H22O11) solution
- Ethanol (C2H5OH)
- Kerosene
- 1M HCl
- 1M NaOH
- Glacial acetic acid (HC2H3O2)
- 6M acetic acid (HC2H3O2)
- 6M ammonia (NH3)
- Distilled water
- Tap water
- Conductivity apparatus
- 100-mL beaker
Procedure:
- Clean and dry beaker.
- Add 20 mL of 5% NaCl solution to the beaker.
- Plug in conductivity apparatus and immerse the electrodes into the solution at a depth
of 1 cm.
- Make observations about the light bulb.
- UNPLUG the conductivity apparatus, and clean and dry electrodes.
- Repeat steps 1-5 with all other solutions.
- Record all information in the data table.
Data & Information:
| Substance |
Bright/Dim/No Light |
. . . . . . . . . . . Why? . . . . . . . . . . . |
| 5% NaCl Solution |
Bright/Dim/No Light |
Why: |
| Distilled Water |
Bright/Dim/No Light |
Why: |
| Tap Water |
Bright/Dim/No Light |
Why: |
| Kerosene |
Bright/Dim/No Light |
Why: |
| 1M HCl |
Bright/Dim/No Light |
Why: |
| 1M NaOH |
Bright/Dim/No Light |
Why: |
| Glacial HC2H3O2 |
Bright/Dim/No Light |
Why: |
| 6M NH4 |
Bright/Dim/No Light |
Why: |
| 1M NH4 |
Bright/Dim/No Light |
Why: |
Questions:
- Compare the conductivity of solid NaCl and a 5% solution of NaCl. Explain the
difference.
- Compare the conductivity of 6M ammonia and 1M ammonia. Explain any difference.
- What type of bonding is present in HCl? Explain the results of the conductivity test on
HCl.
- Glacial acid is acetic acid that is 99.8%, containing no more than 0.2% water. Compare
the conductivity of glacial acid with that of 6M acetic acid and explain the difference.